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A man has two children. One of them is a boy.



halbpro

Well-known member
Jan 25, 2012
2,902
Brighton
Hans, with all due respect (i.e. none at all..!), this is nonsense. How on earth is b/g a different outcome to g/b when you are not worried about the order...?

I was following with HKFC, but you've torn my world asunder here. You're right, at least I think so. Girl/boy and boy/girl are of course identical if you don't care about which is the older sibling.

So you do start with:

1. Boy/boy
2. Boy/girl
3. Girl/boy
4. Girl/girl

And you have a roughly 25% chance of each. By stating one of them is a boy you eliminate 4, and as you don't care about which sibling is which you combine 2 and 3 down to a single option, leaving you with a simple 50/50 chance.

Now does the order matter? If you were to say "The older sibling is a boy" then you can again eliminate option 4, and while you can't combine 2 and 3 you can eliminate 3 because the older sibling (the first one) is a girl. So you're still left with 50/50.
 




Diablo

Well-known member
Sep 22, 2014
4,385
lewes
I was following with HKFC, but you've torn my world asunder here. You're right, at least I think so. Girl/boy and boy/girl are of course identical if you don't care about which is the older sibling.

So you do start with:

1. Boy/boy
2. Boy/girl
3. Girl/boy
4. Girl/girl

And you have a roughly 25% chance of each. By stating one of them is a boy you eliminate 4, and as you don't care about which sibling is which you combine 2 and 3 down to a single option, leaving you with a simple 50/50 chance.

Now does the order matter? If you were to say "The older sibling is a boy" then you can again eliminate option 4, and while you can't combine 2 and 3 you can eliminate 3 because the older sibling (the first one) is a girl. So you're still left with 50/50.

WTF are you serious.............
 




hans kraay fan club

The voice of reason.
Helpful Moderator
Mar 16, 2005
62,759
Chandlers Ford
I was following with HKFC, but you've torn my world asunder here. You're right, at least I think so. Girl/boy and boy/girl are of course identical if you don't care about which is the older sibling.

So you do start with:

1. Boy/boy
2. Boy/girl
3. Girl/boy
4. Girl/girl

And you have a roughly 25% chance of each. By stating one of them is a boy you eliminate 4, and as you don't care about which sibling is which you combine 2 and 3 down to a single option, leaving you with a simple 50/50 chance.

Now does the order matter? If you were to say "The older sibling is a boy" then you can again eliminate option 4, and while you can't combine 2 and 3 you can eliminate 3 because the older sibling (the first one) is a girl. So you're still left with 50/50.

A man has two coins. He decides to spin both.

Question
"What is probability of both landing on heads"
Answer
25%. Only one of four possible outcomes is heads/heads.

Or would you 'combine' the h/t and the t/h possibilities into one, and call it 1 in 3 possibilities? No, you wouldn't.
 


Diablo

Well-known member
Sep 22, 2014
4,385
lewes
I'm serious in my answer to this particular line of reasoning. I won't commit any further than that.

I`ve got three children two of whom are boys...is this ambiguous or can you work out that my third is................................................................a girl.
 




Dec 29, 2011
8,204
I was following with HKFC, but you've torn my world asunder here. You're right, at least I think so. Girl/boy and boy/girl are of course identical if you don't care about which is the older sibling.

So you do start with:

1. Boy/boy
2. Boy/girl
3. Girl/boy
4. Girl/girl

And you have a roughly 25% chance of each. By stating one of them is a boy you eliminate 4, and as you don't care about which sibling is which you combine 2 and 3 down to a single option, leaving you with a simple 50/50 chance.

Now does the order matter? If you were to say "The older sibling is a boy" then you can again eliminate option 4, and while you can't combine 2 and 3 you can eliminate 3 because the older sibling (the first one) is a girl. So you're still left with 50/50.

You can't just 'combine it down to 50%'. Think of 100 families with a distribution such that 25% have 2 two girls, 25% have a boy and a boy, 25% have a girl and a boy and 25% have two boys. The question says at least one child is a boy, so now it's 33% for BG, BB and GB. Obviously the age of sibling isn't stated so we can add GB and BG together because they're essentially the same, so it's 66% for GB/BG, but as we already knew the first was a boy it means there is a 66% chance the other is a girl, hence 33% the other is a boy.

A similar argument can be put forward for 50% but I have no battery left, hopefully I can get it out later.
 


halbpro

Well-known member
Jan 25, 2012
2,902
Brighton
A man has two coins. He decides to spin both.

Question
"What is probability of both landing on heads"
Answer
25%. Only one of four possible outcomes is heads/heads.

Or would you 'combine' the h/t and the t/h possibilities into one, and call it 1 in 3 possibilities? No, you wouldn't.

You can combine them if you know the answer to one though surely? Are we talking about a difference between flipping a coin twice and flipping two coins at the same time?
 


Moshe Gariani

Well-known member
Mar 10, 2005
12,199
A man has two coins. He decides to spin both.

Question
"What is probability of both landing on heads"
Answer
25%. Only one of four possible outcomes is heads/heads.

Or would you 'combine' the h/t and the t/h possibilities into one, and call it 1 in 3 possibilities? No, you wouldn't.
What is the capital of Kenya?
 






pastafarian

Well-known member
Sep 4, 2011
11,902
Sussex
Hello,how many children do you have?
I have two children,one is a boy
Ah a boy and a girl lucky you
Actually the other one is a boy as well
so you have two children and both are boys
yes
why didn’t you say that then
I don’t have to be specific from the outset
you are a dick
 






Goldstone1976

We Got Calde in!!
Helpful Moderator
NSC Patron
Apr 30, 2013
14,124
Herts
Is the boy a Syrian, Islamic refugee?

We need a broader cross section of NSC opinion on this important topic - I'm hoping that the judicious use of certain key words in this post will draw in the NSC intelligentsia.
 


halbpro

Well-known member
Jan 25, 2012
2,902
Brighton
I`ve got three children two of whom are boys...is this ambiguous or can you work out that my third is................................................................a girl.

There's a difference between my answer to the question and my thoughts on a particular line of reasoning.
 


hans kraay fan club

The voice of reason.
Helpful Moderator
Mar 16, 2005
62,759
Chandlers Ford
You can combine them if you know the answer to one though surely? Are we talking about a difference between flipping a coin twice and flipping two coins at the same time?

But in the original question we don't know the answer to either. We know that one is a boy, but not which one. Most are choosing to read it as 'there is a boy, what is the probability of THE OTHER being a boy', which is absolutely 50%. However the question doesn't say that. It says at least one is a boy. Either could be that one, which is why you can't 'combine' the two possible b+g outcomes.
 




halbpro

Well-known member
Jan 25, 2012
2,902
Brighton
But in the original question we don't know the answer to either. We know that one is a boy, but not which one. Most are choosing to read it as 'there is a boy, what is the probability of THE OTHER being a boy', which is absolutely 50%. However the question doesn't say that. It says at least one is a boy. Either could be that one, which is why you can't 'combine' the two possible b+g outcomes.

Ok, you've swung me back for now. I'm very fickle.
 


Moshe Gariani

Well-known member
Mar 10, 2005
12,199
You can't just 'combine it down to 50%'. Think of 100 families with a distribution such that 25% have 2 two girls, 25% have a boy and a girl, 25% have a girl and a boy and 25% have two boys. The question says at least one child is a boy, so now it's 33% for BG, BB and GB. Obviously the age of sibling isn't stated so we can add GB and BG together because they're essentially the same, so it's 66% for GB/BG, but as we already knew the first was a boy it means there is a 66% chance the other is a girl, hence 33% the other is a boy.

A similar argument can be put forward for 50% but I have no battery left, hopefully I can get it out later.
This reminds me of Mrs Pepperpot calculating daily hours of activity.

We are not working with your chosen distribution as the distribution under discussion categorically does not include any possibility of the outcome being two girls.

In this distribution 50% have two boys and 50% have one of each.
 


Triggaaar

Well-known member
Oct 24, 2005
53,153
Goldstone
There is limited or no REAL ambiguity in the original question. He found out one is male because I clearly told him in the question. I don't see how this reworded question is different.
I think it matters. This is why.

Easy part 1:
Let's consider 100 couples have a baby. Half have a boy, half have a girl.
Now let's consider they all have a second baby, half having a boy, half a girl.

Hopefully most of us would agree that 25% have 2 boys, 25% have 2 girls, and 50% have one of each.

Easy part 2:
If I walked up to a random couple and said 'do you have a boy, yes or no?' and they said yes, then the chances of their other child being a boy would be 1 in 3 (because 75% of the couples would have said yes, and of those, 1 in 3 (25% of total) would have a second and 2 in 3 (50% of total) would have a girl.

But the point is, I didn't find out by walking up to one of the couples and asking a specific question. That's not what happened, so I can't make the same deductions.

Difficult part:
A random couple was chosen from the 100, and a random gender was told to me.
Say we ran this test 100 times, and each couple was chosen once. For the 25 couples with 2 girls, I'd be told one was a girl. For the 25 with 2 boys I'd be told one was a boy. For the 50 couple with one of each, 25 times I'd be told one was a girl and 25 times I'd be told one was a boy.
So on 50 occasions I'd be told one was a boy. In 25 of those cases, the other would be a girl, and in 25 of those case one would be a boy.

It's 50%!
 


Dec 15, 2014
1,979
Here
Hello,how many children do you have?
I have two children,one is a boy
Ah a boy and a girl lucky you
Actually the other one is a boy as well
so you have two children and both are boys
yes
why didn’t you say that then
I don’t have to be specific from the outset
you are a dick

What percentage of conversations have these kind of misunderstandings? Or is this question too ambigious?
 




hans kraay fan club

The voice of reason.
Helpful Moderator
Mar 16, 2005
62,759
Chandlers Ford
This reminds me of Mrs Pepperpot calculating daily hours of activity.

We are not working with your chosen distribution as the distribution under discussion categorically does not include any possibility of the outcome being two girls.

In this distribution 50% have two boys and 50% have one of each.

Let's run with this.

Do you think (in general, rather than within the confines of this question), there is the SAME probability of a two-child family having two boys, as there is they'll end up with one of each?
 


fat old seagull

New member
Sep 8, 2005
5,239
Rural Ringmer
I've given myself a feckin migraine just reading the complexities of this thread, much of which I don't understand. The one input I am able to offer is...I have two boys, and neither of them are Ronnie Pickering! :mad:
 


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