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6 - 1 x 0 + 2 / 2 =

6 - 1 x 0 + 2 / 2

  • 1

    Votes: 208 39.0%
  • 2

    Votes: 4 0.8%
  • 3

    Votes: 1 0.2%
  • 4

    Votes: 14 2.6%
  • 5

    Votes: 84 15.8%
  • 6

    Votes: 28 5.3%
  • 7

    Votes: 190 35.6%
  • 8

    Votes: 1 0.2%
  • 9

    Votes: 3 0.6%

  • Total voters
    533










Herr Tubthumper

Well-known member
NSC Patron
Jul 11, 2003
62,697
The Fatherland
Is the answer what I think it is or is there a twist to this question?
 






coagulantwolf

New member
Jun 21, 2012
716
7 I think. (I voted 5, before realising my mistake).

BIDMAS (Brackets, Indices, Division, Multiplication, Addition, Subtracation)

6 - 1 x 0 + 2 / 2
First thing to do is division (2/2=1)
6 - 1 x 0 + 1
Next Multiplication (1x0=0)
6 - 0 + 1 = 7

I think..
 


Bozza

You can change this
Helpful Moderator
Jul 4, 2003
57,289
Back in Sussex
I believe 7 is the answer. I've not looked, it's just the way I understand the correct order of operations from school days from way back when.
 


Dec 29, 2011
8,204
BODMAS. You do the addition before the subtraction.

At the stage 6 - 0 + 1 [so it'd be 6 - (0+1)] you'd add 0 + 1 = 1 and then 6 - 1 = 5. Shirley?
 






Driver8

On the road...
NSC Patron
Jul 31, 2005
16,214
North Wales
BODMAS. You do the addition before the subtraction.

At the stage 6 - 0 + 1 [so it'd be 6 - (0+1)] you'd add 0 + 1 = 1 and then 6 - 1 = 5. Shirley?

My daughter who is studying maths at Uni reckons it is 7 as once the multiplication and division is done you do it in order if there are no brackets.

I also answered 7!
 


Reinelt12

Sick Note
Nov 8, 2006
1,314
Lichfield, United Kingdom
BODMAS. You do the addition before the subtraction.

At the stage 6 - 0 + 1 [so it'd be 6 - (0+1)] you'd add 0 + 1 = 1 and then 6 - 1 = 5. Shirley?

The problem is that you do the division first 2/2 = 1
Then the multiplication -1 x 0 = 0 (so remove from the equation - this is the bit i got wrong as I thought the minus would carry over to the 2/2 but it was cancelled out)
Then add 6 + 1 = 7
 






Surrey Phil

Well-known member
Aug 3, 2010
1,531
Also I have literally no idea how anyone could get 1.

6 - 1 = 5 x 0 = 0 + 2 = 2 / 2 = 1

There did it.

Seems to me you can work this as many ways as you like and come up with lots of different answers but how many times do you read a sentence from the end, then the middle, then the start?
 


Dec 29, 2011
8,204
The problem is that you do the division first 2/2 = 1
Then the multiplication -1 x 0 = 0 (so remove from the equation - this is the bit i got wrong as I thought the minus would carry over to the 2/2 but it was cancelled out)
Then add 6 + 1 = 7

Why can't stage two be [6 - (0 x 1) + 1] which would give [6 - 0 + 1] which would give [6 - 1]. I'm not being picky, a genuine question.
 




Dec 29, 2011
8,204
6 - 1 = 5 x 0 = 0 + 2 = 2 / 2 = 1

There did it.

Seems to me you can work this as many ways as you like and come up with lots of different answers but how many times do you read a sentence from the end, then the middle, then the start?

Oh yeah I see, cheers
 


Bean

Registered User
Feb 13, 2010
3,557
Hove
I got it right!
 




Josimojo

New member
Aug 4, 2011
125
Why can't stage two be [6 - (0 x 1) + 1] which would give [6 - 0 + 1] which would give [6 - 1]. I'm not being picky, a genuine question.

I agree with this, surely minus 0 isn't a number, you can't have minus zero of something,
therefore 6 - 0 + 1 =
6 - + 1= 5
 




Josimojo

New member
Aug 4, 2011
125
Although at the point of 6 - 0 + 1 we are allowed to rearrange the numbers in any way we like, so 6 + 1 - 0, or (+) 1 - 0 + 6. So actually I'm changing to 7!
 




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