seagulls4ever
New member
- Oct 2, 2003
- 4,338
SPOILER BELOW
The chance of getting an orange sweet first time = 6/n where n is the total number of sweets.
Having already taken an orange sweet, the chance of getting an orange sweet next time = 5/(n-1)
The probability of both being orange sweets is one third, so 6/n x 5/(n-1) = 1/3
Or (6x5)/n(n-1) = 1/3
Then 30/(n^2-n) = 1/3
(3x30)/(n^2-n) = 1
90/(n^2-n) = 1
90=n^2-n
n^2-n-90=0
QED
n is obviously 10, but that wasn't the question.
I passed my O level maths in 1985.
Finally someone comes out with the proper answer, although people weren't helped by not being given the actual question in the original post. Of course n = 10, but as you say, that wasn't the question. As you see in these worked answers, 10 doesn't appear in any of them. Wonder how many people claiming how easy it is could actually get the full marks?