Couple of logic puzzles..

[Nibble]

That is tough, still thinking....

 

[Eric Potts]

THe poison was in a dissolvable capsule , which hadn't begun to dissolve when he had the punch

 

[Nibble]

And only a minute behind me

You are quite right, apologies you got them first.

 

[Bozza]

THe poison was in a dissolvable capsule , which hadn't begun to dissolve when he had the punch

You're on the right lines.

 

[Yorkie]

Poisoned ice cubes

 

[Bozza]

And only a minute behind me

Some of us have work to do...

 

[Bozza]

Poisoned ice cubes

That's it. The ice cubes were still solid when our man drank the punch. They subsequently melted poisoning everyone else.

 

[Nibble]

Poisoned ice cubes

It's got to be, nice thinking. Bozza?

 

[tedebear]

he was already dead because his mother in law vexed him and he trod on a rusty nail?

 

[tedebear]

oh poo - thought I was close there...

 

[nail-Z]

Here's another to mull over.

You have a set of balancing scales and 8 balls. 1 of the balls is heavier than the other 7.

What is in MINIMUM number of weighs required to guarantee you know which the heaviest ball is.

 

[Yorkie]

That's it. The ice cubes were still solid when our man drank the punch. They subsequently melted poisoning everyone else.

Thanks to Eric Potts for giving me the clue.

 

[Nibble]

Here's another to mull over.

You have a set of balancing scales and 8 balls. 1 of the balls is heavier than the other 7.

What is in MINIMUM number of weighs required to guarantee you know which the heaviest ball is.

Bloody hell, errm...

 

[Nibble]

Would it be one? If you have one weight in one scale and then place each ball in the other scale separately one at a time, would that tell you the heaviest ball?

 

[Bozza]

3 is the obvious answer...

Assume balls numbered 1 to 8 and, say, 6 is the heaviest.

weigh 1, 2, 3 and 4 against 5, 6, 7, 8. Discard 1-4

Weigh 5 and 6 against 7 and 8. Discard 7 and 8.

Weigh 5 against 6 and discover 6 is the heaviest.

But as 3 is the obvious answer I assume there is a cunning answer of 2.

 

[nail-Z]

Would it be one? If you have one weight in one scale and then place each ball in the other scale separately one at a time, would that tell you the heaviest ball?

No. Each time you replace a ball it counts as a weigh, so could require up to 7 tests.

It is possible to do it in 2 though.

 

[Adam Virgo's Shirt]

None because you can tell 'by feel' which is the heaviest when you pick them up?

 

[Nibble]

It is a bit lost on me this, not good at thinking logically when figures are involved.

 

[nail-Z]

None because you can tell 'by feel' which is the heaviest when you pick them up?

It's good...


...but it's not right.

 

[tedebear]

4 balls in one 4 balls in the other, discard the lightest lot, 2 balls in each, discard the lightest again, 1 ball in each discard the lightest...

3 weighs?