O/T Calling all MATHS geniuses

[sten_super]

I'm a bit rusty but I'll have a go:

Y+1 = (100/P) ^ (360/D)
(Y+1)^D = (100/P)^360
(Y+1)^(D/360) = 100/P
P*((Y+1)^(D/360)) = 100
P = 100/((Y+1)^(D/360))


....or what Seagull27 said

Aha yes. I got the same result as you but didn't click that 100*(Y+1)^(-D/360) is the same as 100/(Y+1)^(d/360).

I get stuck or go majorly wrong around the point where is stop:
Y=(100/P)^(360/D) -1
Y+1=(100/P)^(360/D)
log Y+1= log(100/P)^(360/D)
log Y+1= (360/D)*log(100/p)
STUCK

well, log(100/p) is the same as log 100 - log P, giving
log Y+1 = (360/d)(log 100 - log P)
then divide both sides by (360/d)
(log Y+1)(D/360) = log 100 - log P
add log P to both sides
log P + (log Y+1)(D/360) = log 100
take away (log Y+1)(D/360) from both sides
log P = log 100 - (log Y+1)(D/360)
using log powers (which was used earlier to go from log(100/p) to 100 - log P
log P = log (100/(Y+1)(D/360))
then de-log; the (D/360) gets applied to the (Y+1) as a power
P = 100/(Y+1)^(D/360)

 

[Wickerman]

Theres an APP for that!!!

 

[34064 Fighter Command]

Maths vs. RE

 

[Badger]

Aha yes. I got the same result as you but didn't click that 100*(Y+1)^(-D/360) is the same as 100/(Y+1)^(d/360).

Then comes the argument over which is the neater answer

 

[ForestRowSeagull]

I got some paper out and solved it now. What i'm surprised at is why the bloody hell do you need to know this ?! I thought maths was just for nerds to pleasure their autistic side.

 

[ForestRowSeagull]

Aha yes. I got the same result as you but didn't click that 100*(Y+1)^(-D/360) is the same as 100/(Y+1)^(d/360).




well, log(100/p) is the same as log 100 - log P, giving
log Y+1 = (360/d)(log 100 - log P)
then divide both sides by (360/d)
(log Y+1)(D/360) = log 100 - log P
add log P to both sides
log P + (log Y+1)(D/360) = log 100
take away (log Y+1)(D/360) from both sides
log P = log 100 - (log Y+1)(D/360)
using log powers (which was used earlier to go from log(100/p) to 100 - log P
log P = log (100/(Y+1)(D/360))
then de-log; the (D/360) gets applied to the (Y+1) as a power
P = 100/(Y+1)^(D/360)

Thanks, once I remembered the log rules I was fine. Hard one though

 

[Codner's Crackpipe]

Gosh, thanks everyone. Only on NSC could it be raining rain men.

I got some paper out and solved it now. What i'm surprised at is why the bloody hell do you need to know this ?! I thought maths was just for nerds to pleasure their autistic side.

It's a yield to price calculation for a Spanish 18 month treasury bill.

 

[essbee]

what a bunch of egg heads!

Could we PLEASE get back to football?

 

[Badger]

Thanks, once I remembered the log rules I was fine. Hard one though

You don't need to use logs though.

 

[Nathan]

Sorry, what was the question again?

 

[Don Quixote]

[MENTION=11992]HseagullsH[/MENTION] will do it for you. He's a maths genius.

 

[Fef]

There was the constipated mathematician who worked it out with a pencil and paper.
When it got too hard he worked it out with axes and logs.

I'll get my coat.

 

[Dr. Notthenineo'clocknews]

Not ashamed to say that none of this means anything to me at all. Way over my head.

I was 'educated' at Moulsecoomb and Falmer during the 70's/80's its a fuckin miracle I know how to get out of bed