fork me
I have changed this
It's the same as the whole 'If a brick and feather are dropped from a height in a vacuum, they fall at the same speed' thing.
Or a ball bearing:
Or a hammer, a much more impressive demonstration:
It's the same as the whole 'If a brick and feather are dropped from a height in a vacuum, they fall at the same speed' thing.
Or a ball bearing:
Now I am confused I thought the original statement suggested that one bullet was fired. Therefore has a propellant charge. The second bullet droped will not hit the ground at the same time. Unless the bullet is fired on the horizontal plane and the bullet droped is on the vertical, then the factors are how close to the firing of the bullet is the second dropped. Unless I have misunderstood this thread then I appologise.
Unless the bullet is fired on the horizontal plane and the bullet droped is on the vertical, then the factors are how close to the firing of the bullet is the second dropped. Unless I have misunderstood this thread then I appologise.
Oh my god, I've just read through this thread and there is a lot of circular argument going on.
To clarify the OP's original statement:
If you are in a vaccuum on a perfectly flat surface and you fire a bullet perfectly horizontally and simultaneously drop a second bullet (or anything else for that matter) then they will hit the ground at the same time because gravity acts on both items equally regardless of horizontal motion. FACT!
Why does the vacuum make a difference? Surely, on the same basis as the rest of the motion, the vertical portion of the drag is the same on both bullets?
Well I'm not a physicist, but I'm guessing that a bullet-shaped object flying horizontally through the air will be acted upon in some way by air resistance/turbulence/friction that may potentially be different from the effects of the air on a bullet that's just dropped. I'm guessing that those differences may potentially affect whether each bullet falls vertically more quickly or more slowly.
I agree it's unlikely to make much difference, but stating that it's in a vacuum eliminates this variable. Another (more complicated) way to eliminate this variable I guess would be to state that the bullet is flawlessly-shaped and is fired from the gun without any spin or other force that could alter its perfectly horizontal trajectory. Also, the air itself would have to be completely still, evenly distributed, same temperature throughout etc...
I understand what you're saying, but I still think the air resistance (still assuming it's fired perfectly horizontally) can be split into two components - one horizontal, acting against its forward motion, and one vertical, acting against the gravitational force pulling it to Earth - and so it doesn't matter. I may of course be wrong too... Who knows...?