[Misc] Are you one of the 4%...

[Deano's Invisible Pants]

A, K and 7.
A to check an even on the other side
K to check there isn't a vowel on the other side (nothing in the question says it is a number on one side and a letter on the other)
7 to check there isn't a vowel on the other side

2 doesn't matter, a vowel having to have an even on the other side does not mean an even must have a vowel on the other side

Is the correct answer

 

[dazzer6666]

Definitely A,K & 7. Any of them could have a vowel on the other side.

 

[Broomfield]

A 2


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[Thunder Bolt]

AK 27 = Anthony Knockaert 27

Am I doing this right?

 

[Kalimantan Gull]

Annoyed I got it wrong, AK7 must be the correct answer

 

[spongy]

AK 27 = Anthony Knockaert 27

Am I doing this right?

Your signature is very apt for this!

 

[Thunder Bolt]

Your signature is very apt for this!

It was a joke, or it tried to be.

 

[Nixonator]

A & 7 surely? Not seeing the trick here

 

[SUA Seagull]

A and 2 methinks.

If a card has to have an even number on one side and a vowel on the other side then K (even if it has an even number) and 7 (even if it has a vowel) will fail that test. So you'd only need to turn over the A to check if there's an even number on the back and 2 to check if there's a vowel on the back.

Would love to know the correct answer as it's bugging me now!

Edit: just reworked this and studied the exact question wording very carefully and now think the above answer is wrong, but I'm not changing it as that wouldn't be fair!

 

[Thunder Bolt]

A & 7

 

[Rock Lobster]

All of them?

 

[skipper734]

Just the 2.

 

[Badger]

I've seen this before and got it wrong because it didn't give the whole story. It's supposed to say that all cards have a number on one side and a letter on the other. In which case, you only need to look at A and 7.

 

[Superphil]

https://vimeo.com/177610958

 

[Driver8]

All of them.

 

[peterward]

Even then K could have an even number behind it.

But it doesn't say a consonant must have an even or odd, only a vowel needs an even. If k had an even or odd number the rule isn't broken, but if k had a vowel the rule is broken, therefore k needs flipping to check for a vowel.

Only 2 doesn't need turning.... If it's a consonant or any number behind 2 that doesn't break rule, as it's not stipulated an even number needs a vowel, only that a vowel needs an even number..... Therefore whatever is behind 2 doesn't break rule. If it's a vowel it has an even, if it's not a vowel there's nothing to say an even number must have a vowel, just a vowel needs even. A, K, 7 only

 

[Wrong-Direction]

What's the effing answer ffs!!!?

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[The Brighton Bear]

What's the effing answer ffs!!!?

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I said earlier, A & 7

 

[Triggaaar]

A, K and 7.
A to check an even on the other side
K to check there isn't a vowel on the other side (nothing in the question says it is a number on one side and a letter on the other)
7 to check there isn't a vowel on the other side

2 doesn't matter, a vowel having to have an even on the other side does not mean an even must have a vowel on the other side

If you did that without help, welcome to the 4% club.

 

[vegster]

Card three, the one with 2 on it, it must have a vowel on the obverse side or the rule is false.